Which term of the AP 3, 15, 27, 39,...... will be 132 more than its 54th term?
a=3 d=15-3=12
Let the term of the ap be añ
añ=a54+132
a+(n-1)d=a+53d+132
Putting the values
3+(n-1)12
=3+53×12+132 3+12n-12
=3+636+132 12n-9
=3+768 12n-9=771 12n
=771+9 12n=780 n
=780/12
n=65
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