Which term of the AP 3, 15, 27, 39,...... will be 132 more than its 54th term?

a=3 d=15-3=12

Let the term of the ap be añ

añ=a54+132 

a+(n-1)d=a+53d+132 

Putting the values 

3+(n-1)12

=3+53×12+132 3+12n-12

=3+636+132 12n-9

=3+768 12n-9=771 12n

=771+9 12n=780 n

=780/12 

n=65